What is the probability that one is not nervous around strangers? The probability that both will be nervous is 0.0324
One is not nervous = 1 - P(None are nervous) - P(Both are nervous)
I feel like it's missing something.. is there any other info?
About 18% of the population of a large country is nervous around strangers. If two people are randomly selected, what is the probability both are nervous around strangers? What is the probability at least one is nervous around strangers?
I got the first part I just need help on the second part. I have no idea where to start and where to end.
oh so there you go, 18% is nervous, so the remaining 82% aren't. P(none are nervous)=0.82 1-.82-.0324
Meaning 1 - P(none are nervous) - P(both are nervous) Have someone double check tho, I'm not too sure about probability
So I would find the remaining and subtract it from 1?
you need to find P that none are nervous, which is 1-.18=.82 P(one out of two is not nervous) = P(only one out of the two is nervous) = 1 - P(none are nervous) - P(both are nervous)
= 1 - 0.82 - 0.0324
0.1476 isn't right.
I don't understand how 0.3276 is the answer.
wait it said at least one,one gives probability of exactly one
I don't understand what you're trying to say.
so P at least one is P exactly one + P exactly two
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