Question

Does an enzyme catalyzed reaction going at Vmax implies that the enzyme is nearly saturated?(no inhibitor present)

Answer 1

Yes it does. You can also see it from math. We define Vmax within the MM-framework as:
\[\Large V_{\max}=k_{cat} \times [E]_T\]
In words this mean, that the highest rate is archived when all enzymes (E_T) is bound as enzyme-substrate complex.