use substition to find x and y (a) x-y=-8 (b) x^2-y=-2
Hi
So these equations must go together, what would you like to solve for x or y is doesn't matter which one we do
Do you know how to solve for x or y?
yeah I know how to solve, I was just wondering how to get rid of the x^2 on the second equation
I rearranged the first equation so it looked lie x=-y-8, then I plugged it into the second equation
You don't have to really red rid of it if these are a system of equations
Or are these separate?
(-y-8)^2 -y=-2 This is what I end up with
You have to use the foil method because remember that (-y-8)^2 means (-y-8)(-y-8)
If something is squared like that it will always be the inside times the inside
Does this make sense?
so it will end up looking like y^2 +8y+8y+64-y=-2
Just a second
I caught something when you moved the y to the other side
It's suppose to be a + not a -
You have to do the opposite so it's subracting y in the original equation so your going to have to add by y so it will be a positive sign
Yes
y^2 +8y+8y+64+y=-2 then combine like terms and you get y^2+17y =-66 (is this right)
Yes
ok, this is where I got
I would keep the 66 on the other side though so you can factor
...stuck (sorry hit enter)
would 11 and 6 work
yes
So than y would equal?
would y have two answers
Yes but 11 and 6 aren't it because you have (y+11)(y+6)=0
I know we would have to set both of those factors = 0 so it's actually -11 and -6
Yes good
ok, so which one do we use to plug back into our equation to get x
It doesn't matter they would both be the same answers but since the first one is easiest I would you the first equation
so if I were to graph this, there should be two spots on the graphs where they touch because we have two sets of ordered pairs right
Hmmmmmmmm
just checked it! And it does have two points
Omg I'm sorry I missed something again It would be easier If I would have done this on paper x=y-8 so you will have a -16y not positive I am so sorry
Because that that would be (y-8)^2 y^2-16x+64-y+2=0
So y^2-17y+66=0
that's okay, I figured that out as well
I don't know why I missed two errors but now you would just get positive y values not negative and than get your corresponding x values
So we were close the first time
Does that make sense?
yep, I figured that out, as soon as I graphed the two equations! Thanks for the help
No problem :)
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