Find the limit of the function algebraically. limit as x approaches zero of quantity x squared plus two x divided by x to the fourth power.
\[\lim_{x \rightarrow 0}\frac{ x ^{2} + 2x }{ x ^{4} }\]
it might help to look at a table of values. Specifically x values that are very close to 0 things like x = -0.5 x = -0.4 x = -0.3 x = -0.2 x = -0.1 x = 0 x = 0.1 x = 0.2 x = 0.3 x = 0.4 x = 0.5
I'm assuming L'Hopitals wouldn't be valid in this situation?
You could use L'Hospitals' rule but only on that current form if you were to simplify like so \[\Large \frac{ x ^{2} + 2x }{ x ^{4} }\] \[\Large \frac{ x(x + 2) }{ x ^{4} }\] \[\Large \frac{ x(x + 2) }{ x*x ^{3} }\] \[\Large \frac{ {\color{red}{x}}(x + 2) }{ {\color{red}{x}}*x ^{3} }\] \[\Large \frac{ {\color{red}{\cancel{x}}}(x + 2) }{ {\color{red}{\cancel{x}}}*x ^{3} }\] \[\Large \frac{ x+2 }{ x ^{3} }\] then L'Hospitals' rule wouldn't work
In my opinion, it's always a good idea to simplify as much as possible before doing the limit
I agree 100%, I just wasn't sure if L'Hopitals was considered algebraically
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