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Mathematics 19 Online
OpenStudy (agent47):

Could someone please explain to me how this got summed?

OpenStudy (agent47):

\[\sum_{i=0}^k \binom ni \binom n{k-i}=\binom {n+n}k\]

OpenStudy (agent47):

I can see that they're just adding the values, but I've been trying to find the pattern over the series for a few hours and don't see it.

OpenStudy (agent47):

@wio

OpenStudy (anonymous):

Hmmm. At first I think of binomial theorem, but it doesn't quite match it.

OpenStudy (anonymous):

I'm thinking of something like this:\[ (x+y)^n = \sum_{k=0}^{n}{n\choose k}x^ky^{n-k} \]

OpenStudy (anonymous):

To the \(n\)th power is permutations replacement

OpenStudy (agent47):

hmm I see what you mean. I'll explore that version in a bit - this was just out of my own curiosity. I'm actually somewhat stuck on this final problem, just tedious and I've had a long day, could you just watch over my work to make sure I don't make any mistakes please?

OpenStudy (anonymous):

I can watch.

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