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Find the \(2 \times 2\) matrix \(A\) such that \(A^2 = A\) and \(A \begin{pmatrix} 7 \\ -1 \end{pmatrix} = \begin{pmatrix} 6 \\ 2 \end{pmatrix}.\)
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One key thing to observe here is that \(A\) is either a singular matrix or the identity matrix : \[A^2 = A \implies \color{red}{A^{-1}} A^2 = \color{red}{A^{-1}} A \implies A = I\] That shows either \(A\) is the identity matrix or it is not invertible.
Let \(A = \begin{bmatrix} x&kx\\y&ky \end{bmatrix}\). Use the given condition and setup two equations.
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