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Mathematics 18 Online
OpenStudy (anonymous):

please help me on this question

OpenStudy (anonymous):

The length of the set..... \[\cup_{k=1}^{\infty} (X : \frac{ 1 }{ k + 1}\le X \le \frac{ 1 }{ k }\] is

OpenStudy (anonymous):

a) 0 b) 1 c) ∞ d) 2

OpenStudy (anonymous):

please show your working . very important

OpenStudy (math_man21):

ray

OpenStudy (math_man21):

and i dont understan tht but i no someone who might

OpenStudy (anonymous):

ok. please tag him here

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@mathmale

ganeshie8 (ganeshie8):

@eliassaab or @zzr0ck3r

OpenStudy (anonymous):

@zzr0ck3r

OpenStudy (anonymous):

@mathmale

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (anonymous):

@mathmale

OpenStudy (mathmale):

I'd suggest you actually write out this inequality for several k values, beginning with k=1, k=2, and so on. Doing this myself, I found that X is always clearly delimited by the lower and upper boundaries defined by the value of k. What is the LONGEST interval within which X might be found, and for which k value does that occur?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

i tried k=1, i got 1/2\[\le x \le1\]

OpenStudy (anonymous):

when i tried k= 2, i got \[1/3 \le x \le 1/2 \]

OpenStudy (anonymous):

and it continued in that pattern but what next should i do?

OpenStudy (math_man21):

oh this prob.

OpenStudy (math_man21):

mathmale

OpenStudy (mathmale):

Again: "What is the LONGEST interval within which X might be found, and for which k value does that occur?"

OpenStudy (mathmale):

Let k=2. What are the upper and lower bounds on X?

OpenStudy (anonymous):

is it infinity?

OpenStudy (mathmale):

No. The left boundary is 1/(k+1). Let k=2 and calculate this boundary.

OpenStudy (anonymous):

yes i have [1/3,1/2]

OpenStudy (anonymous):

@mathmale

OpenStudy (mathmale):

You have the two boundaries (1/3) and (1/2) when k=2. (1/3) is less than (1/2), so this makes perfect sense. Now let k have the smallest possible value allowed by the question: 1. Calculate the lower and upper boundaries, please.

OpenStudy (anonymous):

for k=1 , i got [1/2,1]

OpenStudy (mathmale):

that is the longest interval you can find that contains X. Does this answer your question or not?

OpenStudy (anonymous):

so, because one is the longest interval generated, the answer is one?

OpenStudy (mathmale):

What is 1 - (1/2)? How did you get 1?

OpenStudy (anonymous):

1/2 is the answer to 1- (1/2)

OpenStudy (anonymous):

So the right option is 1 which is b

OpenStudy (mathmale):

Do you have any way in which you could contact your teacher or course administrator? I asked you to find 1 - (1/2), which comes out to 1/2, so how could the "length" of the set be 1? You may have to clear this up with your teacher.

OpenStudy (anonymous):

OK . But is the 1/2 same as its measure?

OpenStudy (anonymous):

@mathmale

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