please help me on this question
The length of the set..... \[\cup_{k=1}^{\infty} (X : \frac{ 1 }{ k + 1}\le X \le \frac{ 1 }{ k }\] is
a) 0 b) 1 c) ∞ d) 2
please show your working . very important
ray
and i dont understan tht but i no someone who might
ok. please tag him here
@ganeshie8
@mathmale
@eliassaab or @zzr0ck3r
@zzr0ck3r
@mathmale
@xapproachesinfinity
@mathmale
I'd suggest you actually write out this inequality for several k values, beginning with k=1, k=2, and so on. Doing this myself, I found that X is always clearly delimited by the lower and upper boundaries defined by the value of k. What is the LONGEST interval within which X might be found, and for which k value does that occur?
yes
i tried k=1, i got 1/2\[\le x \le1\]
when i tried k= 2, i got \[1/3 \le x \le 1/2 \]
and it continued in that pattern but what next should i do?
oh this prob.
mathmale
Again: "What is the LONGEST interval within which X might be found, and for which k value does that occur?"
Let k=2. What are the upper and lower bounds on X?
is it infinity?
No. The left boundary is 1/(k+1). Let k=2 and calculate this boundary.
yes i have [1/3,1/2]
@mathmale
You have the two boundaries (1/3) and (1/2) when k=2. (1/3) is less than (1/2), so this makes perfect sense. Now let k have the smallest possible value allowed by the question: 1. Calculate the lower and upper boundaries, please.
for k=1 , i got [1/2,1]
that is the longest interval you can find that contains X. Does this answer your question or not?
so, because one is the longest interval generated, the answer is one?
What is 1 - (1/2)? How did you get 1?
1/2 is the answer to 1- (1/2)
So the right option is 1 which is b
Do you have any way in which you could contact your teacher or course administrator? I asked you to find 1 - (1/2), which comes out to 1/2, so how could the "length" of the set be 1? You may have to clear this up with your teacher.
OK . But is the 1/2 same as its measure?
@mathmale
Join our real-time social learning platform and learn together with your friends!