The following data values represent a population. What is the variance of the values?
6, 10, 14, 2
A. 20
B. 16
C. 8
D. 10
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OpenStudy (anonymous):
@pooja195
OpenStudy (anonymous):
Can you find the expected value first?
OpenStudy (anonymous):
The mean, I mean
OpenStudy (anonymous):
how u find mean wit even set
OpenStudy (anonymous):
\[
\frac{1}{|A|}\sum_{a\in A}a
\]
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OpenStudy (anonymous):
o.0 wut is that
OpenStudy (anonymous):
In this case: \[
\frac{6+10+14+2}{4}
\]
OpenStudy (anonymous):
pls explain
OpenStudy (anonymous):
The mean is the sum of all the numbers, divided by how many numbers there are.
OpenStudy (anonymous):
sum is add
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OpenStudy (anonymous):
32/4?
OpenStudy (anonymous):
8?
OpenStudy (anonymous):
thank u, can u help with more? im still struggling
OpenStudy (anonymous):
The mean is 8.
OpenStudy (anonymous):
Now for variance, we have to plug each value into (8-x)^2 add them, and then divide by the number of numbers. The 8 is there because it is the mean.
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OpenStudy (anonymous):
The mean is \(\mu\):\[
\mu =\frac{1}{|X|}\sum_{x\in X}x
\]The variance is \(\sigma^2\):\[
\sigma^2=\frac{1}{|X|}\sum_{x\in X}(x-\mu)^2
\]Where as \(\sigma\) is standard deviation.