Question

A grinding wheel 0.46 m in diameter rotates at 1800 rpm.
(a) Calculate its angular velocity in rad/s.
(b) What are the linear speed and acceleration of a point on the edge of the grinding wheel?

So for (a) i got 188.5 rad/s and for (b), i got the linear velocity to be 43.36 m/s. I don't know how to get the acceleration without a time frame though. Can someone help?

Answer 1

rpm=revolution per minute

Answer 2

Angular velocity = 2*pi*f

Answer 3

Centripetal acceleration in a uniform circular motion is: \(r\,\omega ^2 \)

Answer 4

f=frequency

Answer 5

f=1800rpm=1800/60 revolution per second

Answer 6

She does not need frequency since she already has worked out angular velocity.

Answer 7

Yes