If the legs of a right triangle are x-3 and 9, and its hypotenuse is x, find the length of its smallest side.
I set up ( x-3 ) ^2 + 9^2 = x^2
so this is a right triangle - do you know Pythagora's theorem ?
Yes
you need just use it and will get what you need
Yeh, but i dont know how set up everything
so what you have wrote above - this equation just you need to solve it for x
okay so x^2 -6x +9 + 81 = x^2 x^2 -6x + 90 = x^2 -6x = 90 so i get -15
But all my friends say positive 15 i dont know how though
there above you have wrote (x-3)^2 +9^2 = x^2 yes ?
yes
but check it please that there is something wrong - after you eliminated the x^2 what will remain there ?
-6x and 90
yes but hence -6x+90 = 0 so what will get the subtract from both sides 90 ?
oh -90
yes sure
resulting in 15 from there
so the smallest side is 9
yes exactly - do you see it now your friends was rights
oh ok yes, so the smallest side was already given
yes - this is ok. now ? do you understand it all sure ?
Yup, thanks
np welcome was my pleasure anytime ---- good luck bye
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