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OpenStudy (pulsified333):
@satellite73
zepdrix (zepdrix):
Remember your exponential derivative?\[\large\rm \frac{d}{dx}e^{stuff}=e^{stuff}\frac{d}{dx}stuff\]We get the same thing back, but with chain rule.
zepdrix (zepdrix):
The -13 is a constant coefficient,
it has no effect on the differentiation process,\[\large\rm \frac{d}{dx}\left(-13e^{-0.9t}\right)=-13\frac{d}{dx}e^{-0.9t}\]
zepdrix (zepdrix):
\[\large\rm =-13e^{-0.9t}\cdot(-0.9t)'\]So just chain rule :)
Multiply by derivative of the exponent.
OpenStudy (pulsified333):
oh okay
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OpenStudy (pulsified333):
@zepdrix that didn't work
zepdrix (zepdrix):
Do you see the ( )' at the end?
The tick mark is to indicate that you need to take the derivative of that portion.
zepdrix (zepdrix):
Do you understand how to take derivative of 0.9t?
OpenStudy (pulsified333):
9/10?
zepdrix (zepdrix):
Good good good.
I should have said -0.9t,
which turns into -0.9 through differentiation.
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zepdrix (zepdrix):
Simplify the problem by multiplying the -13 and -0.9 together.