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Well the total liters they need is 100000 Each trailer can carry 2400 + 2200 = 4600 liters So how many trailers would it take? \[\large \frac{100000}{4600} = ?\]
that should be around 22
i was thinking it would be 2400x + 2200y = 100000
and then have the inequality of x >= y >= 0
(to fulfill the contract)
It would be like that if the trailers could run by themselves, but they're just attached to the tankers...so they just fall in with them
But as far as I see.....22 is correct :)
oh :/
I don't think it is, it's supposed to be a greatest common divisor question
Aww why the face :( hmm, lets see...maybe I'm missing something here
Haha sorry, but there's no way it can be that easy
No I agree if its not just a simple algebra problem lol...trying to see what I'm missing :P
I did come up with a solution though, don't know if it's right though
Actually, what did you come up with?
well basically there are 4 possible solutions for the equation 12x + 11y = 500
(divided by 200)
we have (5,40), (16,28), (27,16) and (38,4)
However, only two of them fall into the inequality condition (which is x >= y >= 0)
which are the last two...
and since x is the number of tanker and y is the number of trailers... we choose the lower x
which is 27.........
SoOoOo yeah.
that's what i'm thinking, hope that makes sense
Nope that is absolutely correct!! haha sorry for thinking it was simpler than it was, haven't worked with euclidean in a while!
are you serious??
Yes!! and your reasoning is perfect as well, exactly the train of thought you needed to have here
oh my gawdddddd..... I need a nap. I've been thinking this was wrong for so long!!
Thanks for helping though! <3
Lol NO!!!! dont second *or like 100x over* guess yourself lol That's what I was doing on my fluid mechanics for the past hour XD Good job <3
B) Thanks!
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