Question

Use the Coordinate Plane below to graph the following linear equation for the range x [0,6] using the equation y=x/2

This graph is a regular (x,y) grid.

Answer 1

@johnweldon1993

Answer 2

Range is for y, not x. Do you mean domain?

Answer 3

Well I am doing a math page and this is exactly what the question is.

Answer 4

Well, anyway. To do this (I'm assuming its referring to domain) you would simply graph the line only for x-values 0-6 with solid endpoints.

Answer 5

The slope is 1/2, so (0,0) *no b-value* to (6,3) in a straight line would work.

Answer 6

This is the graph

https://s3.amazonaws.com/atlas-production.goalbookapp.com/uploaded_images%2F486691e7-bda7-47a1-7f7d-73ee2df80e68%2F7980$Screen+Shot+2015-04-07+at+6.44.06+PM.png

Answer 7

Just make sure to finish it with solid endpoints, not arrows.

Answer 8

I made the endpoints huge to point them out, you don't have to.

Answer 9

Ok Is that the whole answer

Answer 10

I can put that

Answer 11

As far as I know, yes.

Answer 12

Ok there are a few more questions that go with this.

Answer 13

@CasidyCat

Answer 14

What is the constant of variation (k) in the equation?

Answer 15

1/2

Answer 16

What is the independent variable in the equation?

Answer 17

Wouldn't it be like x or something like that

Answer 18

yep!

Answer 19

What is the dependent variable in the equation?

Answer 20

Would that be y

Answer 21

@CasidyCat

Answer 22

Right again!

Answer 23

Sorry @CasidyCat I accidentally clicked on it and just decided to look.

Answer 24

Hello

Answer 25

from the other side

Answer 26

I'm such a troll

Answer 27

What does that mean

Answer 28

What is the dependent variable

Answer 29

y

Answer 30

What are the coordinates when x = 40?

@CasidyCat - I have to go to bed but when I get up I will see you answer. Thanks so much for your help!

Answer 31

I will actually just wait until you are done

Answer 32

They don't exist. Remember, the domain stated that 6 was the largest possible x-value. What a tricky, tricky question.

Answer 33

Ok...Thanks so much and I will talk to you later

Answer 34

Okay! Let me know if you need more help!