Question

Question on combining complex terms .

Answer 1

See circled in red.

Answer 2

How do the 2 complex values equate to 3?

Answer 3

\[\large\rm \frac{3}{1+3i \omega}+\frac{9i \omega}{1+3i \omega}\quad=\quad\frac{3+9i \omega}{1+3i \omega}\]From here, factor a 3 out of each term in the numerator,\[\large\rm =\frac{3(1+3i \omega)}{1+3i \omega}\]

Answer 4

\[\large\rm =\frac{3\cancel{(1+3i \omega)}}{\cancel{1+3i \omega}}\]Understand? :)

Answer 5

are you finding the transfer function at resistor ?