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Chemistry 6 Online
OpenStudy (kkutie7):

I'm running short on time and I need help understanding this problem.

OpenStudy (kkutie7):

1.70 x 10-5 M ML was found to generate a detector response of 426 mV at 532 nm. When a non-absorbing species was placed into the cuvette, the detector response measured was 765 mV at 532 nm. Calculate\[\epsilon \].

OpenStudy (aaronq):

\(\epsilon\) is the dielectric constant?

OpenStudy (aaronq):

Or molar absorptivity constant?

OpenStudy (kkutie7):

molar absorptivity

OpenStudy (kkutie7):

do I use the mV as power in vs power out?

OpenStudy (aaronq):

mV is the reading. I could be mistaken, but it seems pretty simple. Basically, the second reading is the blank. \(A_1-A_2=\epsilon*(M_1-M_2)\rightarrow \epsilon=\dfrac{A_1-A_2}{M_1-M_2}\)

OpenStudy (aaronq):

that's just Beer's law, btw

OpenStudy (kkutie7):

M=mass? and A=absorbance... I understand beer's law just not in this context. I know nothing about the blank but the reading. I just don't get it

OpenStudy (aaronq):

M is the molarity, and A absorbance. The second solution is the blank because it contains no absorbing species. |dw:1456368878671:dw| This is analogous to finding the slope of a line using y=mx+b using 2 points. Except here the two points are A and M \(\sf A=\epsilon*l*M\)

OpenStudy (aaronq):

except the two coordinates are A and M**, i meant

OpenStudy (aaronq):

solution 1: \(A_1=\epsilon*l*M_1\) solution 2: \(A_2=\epsilon*l*M_2\) solution 1 - solution 2 \(A_1-A_2=(\epsilon*l*M_1)-(\epsilon*l*M_2)\)

OpenStudy (aaronq):

i gotta get going, hope this makes more sense. Let me know if you still have doubts, ill check it out tmrw

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