Question

rx+9/5=h
please help!!!!!!!!
The division bar would be a fraction so it would be rx+9 for the numerator and 5 for the denominator, please help

Answer 1

Solve for?

Answer 2

solve for x

Answer 3

So this was kinda like the first one you asked so you have to do the adding and subtracting first so what would you have to move to the other side to get x closer to being by itself?

Answer 4

Do you understand?

Answer 5

You would have to subtract 9/5 and bring it to the other side

Answer 6

Do you need me to draw it out?

Answer 7

yes please

Answer 8

https://www.twiddla.com/2550825

Answer 9

Just click on the link

Answer 10

I can't add a drawing because I'm on an ipad

Answer 11

Or can't you?

Answer 12

I can't help you if you don't click on the link, it's only a website so you can see what I'm doing with the problem, it's not going to hurt your computer

Answer 13

I can't attach a file or do a drawing for some reason on here @j.nejad

Answer 14

thank you

Answer 15

Don't want to use the link?

Answer 16

You don't have to sign up or anything

Answer 17

Than I can explain really fast too

Answer 18

Sorry

Answer 19

could u go on the link?

Answer 20

I hope that helps i'm sorry i'm so tired

Answer 21

So you do you adding/subtracting first thab multiplacation/division next

Answer 22

\[\frac{rx+5}{9}=h\]
you need to do multiplication or division first.
In order to do addition or subtraction there needs to be more than one piece of information on the left hand side. please let me see your first step so I can help you.

Answer 23

I have to log off soon so if you want my help we need to hurry this up :P

Answer 24

*explanation examples*
division or multiplication first:
\[\frac{1x}{2}=y \rightarrow 1x=2y\rightarrow x=2y\]
\[5x=y\rightarrow x=\frac{y}{5}\]
Addition or subtraction:
\[2x+5=y\rightarrow 2x=y-5 \rightarrow x=\frac{y-5}{2}\]
or
\[2x-5=y\rightarrow 2x=y+5 \rightarrow x=\frac{y+5}{2}\]
A little bit more complicated. Addition and subtraction with fractions:
\[\frac{7x}{2}+\frac{3}{5}=y\rightarrow \frac{7x}{2}=y-\frac{3}{5}\rightarrow 7x=2(y-\frac{3}{5})\rightarrow \frac{2(y-\frac{3}{5})}{7}=x\]