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Mathematics 20 Online
OpenStudy (sbuck98):

First person to solve gets medal, fan, and help in another subject.

OpenStudy (sbuck98):

OpenStudy (anonymous):

30-60-90 triangles are always in the format|dw:1456441777453:dw|

OpenStudy (anonymous):

So based on this what do you think x equals?

OpenStudy (sbuck98):

15

OpenStudy (sbuck98):

@Brill

OpenStudy (anonymous):

No The side it gives you in your problem is the one across from the 60 degree angle In the diagram I gave you the side across from the 60 degrees is sqrt3 times x Or in other words\[x \sqrt{3}=15\]

OpenStudy (anonymous):

How could you solve for x in the situation?

OpenStudy (sbuck98):

|dw:1456449861328:dw| @Brill

OpenStudy (anonymous):

Are you sure? Wouldn't you isolate x by DIVIDING sqrt3?

OpenStudy (sbuck98):

I didn't think you did.

OpenStudy (sbuck98):

@Brill

OpenStudy (sbuck98):

Help me with 3 more?

OpenStudy (anonymous):

Wait I'd be glad to but what was your answer for the previous one because the drawing is incorrect

OpenStudy (sbuck98):

D. @Brill

OpenStudy (anonymous):

Uhh D is incorrect

OpenStudy (sbuck98):

So B is my only other option....... @Brill

OpenStudy (anonymous):

No it isn't

OpenStudy (anonymous):

Remember when you divide 15 by sqrt3 you have to rationalize

OpenStudy (sbuck98):

I told you 5 sqrt 3 and you said no.....

OpenStudy (sbuck98):

@Brill

OpenStudy (anonymous):

OH MY BAD I AM SO VERY SORRY I FORGOT TO SIMPLIFY 15sqrt3/3 I AM SO SO VERY SORRY

OpenStudy (anonymous):

I didn't even look at the other options

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