Mathematics
20 Online
OpenStudy (tylermckinney16):
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! FAN+METAL
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OpenStudy (tylermckinney16):
HELP ME LOL
OpenStudy (anonymous):
which one do you want to do first?
OpenStudy (tylermckinney16):
Theres only one question lol.
OpenStudy (anonymous):
true, but it is asking for two numbers
OpenStudy (tylermckinney16):
Oh lets do X first.
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OpenStudy (anonymous):
actually we can find them both at the same time
OpenStudy (tylermckinney16):
Cool
OpenStudy (anonymous):
is it clear that the missing angle is 30 degrees?
OpenStudy (tylermckinney16):
yeah
OpenStudy (anonymous):
ok the ratios of the sides of a 30, 60, 90 right triangle is always \[1:\sqrt3:2\]
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OpenStudy (anonymous):
in other words, the short leg is half the hypotenuse, and the long leg is the short leg times \(\sqrt3\)
OpenStudy (anonymous):
you are given the long leg right?
OpenStudy (tylermckinney16):
yeah
OpenStudy (anonymous):
so to get the short leg, divide by \(\sqrt3\) to get \[\frac{33}{\sqrt3}\] which you can rewrite if you like without the radical in the denominator
OpenStudy (anonymous):
do you know how to do that ?
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OpenStudy (tylermckinney16):
no
OpenStudy (anonymous):
\[\frac{33}{\sqrt3}=\frac{33}{\sqrt3}\times \frac{\sqrt3}{\sqrt3}=\frac{33\sqrt3}{3}=11\sqrt3\]
OpenStudy (tylermckinney16):
Ok
OpenStudy (tylermckinney16):
@satellite73
Directrix (directrix):
Satellite found x.
That leaves y, the hypotenuse.
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OpenStudy (tylermckinney16):
ok
OpenStudy (tylermckinney16):
@Directrix
Directrix (directrix):
The hypotenuse is twice the 30 leg with measure x.
y = 2 * 11* √3 = 22√3 <-----
x = 11√3 from above post
OpenStudy (tylermckinney16):
Ok and Y is the thing you just put with the arrow pointing?
OpenStudy (tylermckinney16):
Thank you so much!!!!!!!!!!!