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Mathematics 20 Online
OpenStudy (tylermckinney16):

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! FAN+METAL

OpenStudy (tylermckinney16):

HELP ME LOL

OpenStudy (anonymous):

which one do you want to do first?

OpenStudy (tylermckinney16):

Theres only one question lol.

OpenStudy (anonymous):

true, but it is asking for two numbers

OpenStudy (tylermckinney16):

Oh lets do X first.

OpenStudy (anonymous):

actually we can find them both at the same time

OpenStudy (tylermckinney16):

Cool

OpenStudy (anonymous):

is it clear that the missing angle is 30 degrees?

OpenStudy (tylermckinney16):

yeah

OpenStudy (anonymous):

ok the ratios of the sides of a 30, 60, 90 right triangle is always \[1:\sqrt3:2\]

OpenStudy (anonymous):

in other words, the short leg is half the hypotenuse, and the long leg is the short leg times \(\sqrt3\)

OpenStudy (anonymous):

you are given the long leg right?

OpenStudy (tylermckinney16):

yeah

OpenStudy (anonymous):

so to get the short leg, divide by \(\sqrt3\) to get \[\frac{33}{\sqrt3}\] which you can rewrite if you like without the radical in the denominator

OpenStudy (anonymous):

do you know how to do that ?

OpenStudy (tylermckinney16):

no

OpenStudy (anonymous):

\[\frac{33}{\sqrt3}=\frac{33}{\sqrt3}\times \frac{\sqrt3}{\sqrt3}=\frac{33\sqrt3}{3}=11\sqrt3\]

OpenStudy (tylermckinney16):

Ok

OpenStudy (tylermckinney16):

@satellite73

Directrix (directrix):

Satellite found x. That leaves y, the hypotenuse.

OpenStudy (tylermckinney16):

ok

OpenStudy (tylermckinney16):

@Directrix

Directrix (directrix):

The hypotenuse is twice the 30 leg with measure x. y = 2 * 11* √3 = 22√3 <----- x = 11√3 from above post

OpenStudy (tylermckinney16):

Ok and Y is the thing you just put with the arrow pointing?

OpenStudy (tylermckinney16):

Thank you so much!!!!!!!!!!!

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