Question

Help with a multiple part question?
write the balanced equation for the reaction of the acetic acid (CH3COOH) and sodium bicarbonate (NaHCO3). What type of reaction took place
I have HC2H3O2+NaHCO3=> NaC2H3O2+H2CO3 and an acid-base reaction is this correct?

Answer 1

\[CH_{3}COOH + NaHCO_{3} \rightarrow NaC_{2}H_{3}O_{2} + H_{2}CO_{3}\]

Answer 2

What you can do Is actually count the number of atoms on both sides

Answer 3

Is it an acid based reaction?

Answer 4

Acid-base*

Answer 5

Yes

Answer 6

Can you help me with a few more questions?

Answer 7

Yes no problem

Answer 8

Alrighty
Calculate the number of moles of 3 NaHCO that were required to
neutralize the COOH 3 CH in the vinegar.
I dont understand how to do this i feel like its simple and im over thinking it

Answer 9

Well @Hope214 look at the reaction above what is the molar ratio of CH3COOH to NaHCO3

Answer 10

i dont know thats where im confused

Answer 11

so how many moles were you given?

Answer 12

3 moles of NaHCO3?

Answer 13

i guess

Answer 14

look at the reaction right? we know that it's balanced. now, we know that one mole of NaHCO3 reacts with 1 mole of CH3COOH right? can you see why?

Answer 15

i dont understand any of this imma go to youtube and look for help videos thanks for your help

Answer 16

\[_1CH3COOH+_1NaHCO3→NaC2H3O2+H2CO3\]

This reaction means that one mole of CH3COOH reacts with 1 mole of NaHCO3