Mathematics
24 Online
OpenStudy (imsleeziboii):
HELP!!!!
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OpenStudy (imsleeziboii):
OpenStudy (imsleeziboii):
@jonasjl
OpenStudy (imsleeziboii):
Hi i need your help with a few more
OpenStudy (imsleeziboii):
i dont really understand this at all. yet again a new lesson
OpenStudy (anonymous):
thats fine had to click off for a minute superintendant walked in the building
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OpenStudy (imsleeziboii):
its all good
rebeccaxhawaii (rebeccaxhawaii):
@jonasjl is helping you
OpenStudy (imsleeziboii):
I know i need your help helping someone else @rebeccaxhawaii
rebeccaxhawaii (rebeccaxhawaii):
no?
OpenStudy (imsleeziboii):
You dont want to help? lol
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OpenStudy (anonymous):
let me know if you need help deducting the answer from that it should be pretty straight forward
OpenStudy (imsleeziboii):
Hmm. I see the graph and the points that lie on teh graph but i need help deducting the answer lol
OpenStudy (imsleeziboii):
@jonasjl
OpenStudy (anonymous):
the bottom one is the base line the top one is the one we need the info from
OpenStudy (anonymous):
what is the slope and the y-int on the top line?
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OpenStudy (imsleeziboii):
Hmm. The equation for slope is y^2-y^1/x^2-x^1
OpenStudy (imsleeziboii):
Right? or is that a different equation
OpenStudy (anonymous):
look at the graph and get the slope remember the slope is rise/run
OpenStudy (anonymous):
slope= -5/3
y-int= (0, -2)
so your equation would be
y=-5/3x-2