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Mathematics 6 Online
OpenStudy (imsleeziboii):

HELP!!!!

OpenStudy (imsleeziboii):

OpenStudy (imsleeziboii):

@jonasjl

OpenStudy (imsleeziboii):

Hi i need your help with a few more

OpenStudy (imsleeziboii):

i dont really understand this at all. yet again a new lesson

OpenStudy (anonymous):

thats fine had to click off for a minute superintendant walked in the building

OpenStudy (imsleeziboii):

its all good

rebeccaxhawaii (rebeccaxhawaii):

@jonasjl is helping you

OpenStudy (imsleeziboii):

I know i need your help helping someone else @rebeccaxhawaii

rebeccaxhawaii (rebeccaxhawaii):

no?

OpenStudy (imsleeziboii):

You dont want to help? lol

OpenStudy (anonymous):

let me know if you need help deducting the answer from that it should be pretty straight forward

OpenStudy (imsleeziboii):

Hmm. I see the graph and the points that lie on teh graph but i need help deducting the answer lol

OpenStudy (imsleeziboii):

@jonasjl

OpenStudy (anonymous):

the bottom one is the base line the top one is the one we need the info from

OpenStudy (anonymous):

what is the slope and the y-int on the top line?

OpenStudy (imsleeziboii):

Hmm. The equation for slope is y^2-y^1/x^2-x^1

OpenStudy (imsleeziboii):

Right? or is that a different equation

OpenStudy (anonymous):

look at the graph and get the slope remember the slope is rise/run

OpenStudy (anonymous):

slope= -5/3 y-int= (0, -2) so your equation would be y=-5/3x-2

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