STATS HELP PLEASE? A standard deck of cards contains 52 cards. One card is selected from the deck. (a) Compute the probability of randomly selecting a six or three. (b) Compute the probability of randomly selecting a six or three or nine. (c) Compute the probability of randomly selecting a queen or diamond.
There's 4 6's and 4 3's What's my next step in solving this problem?
Would I divide 6/52*3/52?
I think the problem is composed of mutually exclusive events, so if I were you I would add individual probabilities. Not 100% sure
a: 8/52 b: 12/52 c: 13+3=16, 16/52
Can you explain that?
Probability of getting a six: 4/52 Probability of getting a three: 4/52 P(6 or 3) = 4/52 + 4/52 = 8/52 or 2/13 Same thing you have to do with the rest.
Thanks:)
Sorry, this site is being unstable and slow to respond. Do not know if that is intended by the management or it's an act of God.
LOL. Maybe an act of God? hahha
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