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Mathematics
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OpenStudy (rainbow_rocks03):
PLZ help me, I will medal for the best answer.
10 years ago
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OpenStudy (rainbow_rocks03):
10 years ago
OpenStudy (rainbow_rocks03):
@KamiBug @jdoe0001
10 years ago
OpenStudy (tacotime):
Hints:
Both of the triangles are equal.
You can use they Pythagorean theorem to find the missing side of a right triangle.
10 years ago
OpenStudy (rainbow_rocks03):
?
10 years ago
OpenStudy (jdoe0001):
|dw:1456529042758:dw| use the pythagorean theorem to find the "width" or opposite side
recall that perimeter is side + side + side + side
10 years ago
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OpenStudy (rainbow_rocks03):
so I do 15+12?
10 years ago
OpenStudy (jdoe0001):
\(\bf \textit{pythagorean theorem}=c^2=a^2+b^2\implies c=\pm\sqrt{a^2+b^2}\)
10 years ago
OpenStudy (rainbow_rocks03):
🤔
10 years ago
OpenStudy (jdoe0001):
well.. hold the mayo, you're needing the opposite so
\(\bf \textit{pythagorean theorem}=hypotenuse^2=adjacent^2+opposite^2
\\ \quad \\
hypotenuse^2-adjacent^2=opposite^2\\ \quad \\ \pm\sqrt{hypotenuse^2-adjacent^2}=opposite\)
10 years ago
OpenStudy (rainbow_rocks03):
😐
10 years ago
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OpenStudy (jdoe0001):
or \(\bf \textit{pythagorean theorem}=c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\)
10 years ago
OpenStudy (rainbow_rocks03):
?
10 years ago
OpenStudy (jdoe0001):
|dw:1456529644752:dw|
10 years ago
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