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Mathematics 19 Online
OpenStudy (rainbow_rocks03):

PLZ help me, I will medal for the best answer.

OpenStudy (rainbow_rocks03):

OpenStudy (rainbow_rocks03):

@KamiBug @jdoe0001

OpenStudy (tacotime):

Hints: Both of the triangles are equal. You can use they Pythagorean theorem to find the missing side of a right triangle.

OpenStudy (rainbow_rocks03):

?

OpenStudy (jdoe0001):

|dw:1456529042758:dw| use the pythagorean theorem to find the "width" or opposite side recall that perimeter is side + side + side + side

OpenStudy (rainbow_rocks03):

so I do 15+12?

OpenStudy (jdoe0001):

\(\bf \textit{pythagorean theorem}=c^2=a^2+b^2\implies c=\pm\sqrt{a^2+b^2}\)

OpenStudy (rainbow_rocks03):

🤔

OpenStudy (jdoe0001):

well.. hold the mayo, you're needing the opposite so \(\bf \textit{pythagorean theorem}=hypotenuse^2=adjacent^2+opposite^2 \\ \quad \\ hypotenuse^2-adjacent^2=opposite^2\\ \quad \\ \pm\sqrt{hypotenuse^2-adjacent^2}=opposite\)

OpenStudy (rainbow_rocks03):

😐

OpenStudy (jdoe0001):

or \(\bf \textit{pythagorean theorem}=c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\)

OpenStudy (rainbow_rocks03):

?

OpenStudy (jdoe0001):

|dw:1456529644752:dw|

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