Question

How do you convert square root to decimals for example 5√2?

Answer 1

I know the answer is 7.1 rounded to one decimal place but my calculator has always figured it out for me and I would like to know how to solve it by hand.

Answer 2

well... by hand can be a bit of unfinished work because \(\bf \sqrt{2}\) is an irrational number for one

silly factoid, ancient greeks didn't like \(\sqrt{2}\) because it was irrational, among other irrational numbers =)

Answer 3

In most cases you can't do an exact conversion of square roots to decimals. Instead, you'll have to use a calculator to find the desired root and then round that off to the desired or specified number of decimal places.

Answer 4

I recall taking a square root manually when in school, just a simple quantity took about half a page =), and that was just the square root, not a cubic or quartic =)

and if I recall correctly, the number was a close approximation, not exact per se

Answer 5

Oh the reason I am wondering is because I always used a converter online not my calculator (I accidentally said calculator) and I cannot use converter for my test. But am not sure how to solve in on my ti-84 when I plug it in it gives me it again 5 √2 again not in decimal form.

Answer 6

hmmm I have hmm actually I have a ti-84 per se.. but mostly use the ti-83 plus....if I recall correctly, that's onthe [mode] or settings you have, there's also a [Math] button you can use, that has conversion options, to float, or fractions or decimals and such

Answer 7

ok I will check, so there are some settings for that?

Answer 8

yes, usually... lemme turn it on

Answer 9

do you happen to have an Android phone/tablet by any chance?

Answer 10

Never mind it works, I was originally trying in on my old ti-30 so I thought it did the same on the 84 but it converted it, sorry about that.

Answer 11

hmm rats, I don't have a ti-84, just 86 and 82 and 83plus
hmm
but on the ti-83plus, you can do conversion from the [Math] button

Answer 12

Yeah I got it to work thanks for the help, I am reviewing my study guide do you know by any chance how to find the slope of a perpendicular line?

Answer 13

a perpendicular line? perpendicular to what though? the Equator?

Answer 14

3x+12y=-18

Answer 15

ok..... what's the slope of that line anyway?

Answer 16

or better yet, can you solve that for "y"? what does it look like?

Answer 17

isn't the slope form y=mx+b so wouldent the 3 be the slope?

Answer 18

Right. Take the given line, find its slope, and from that slope, find the slope of a line perpendicular to the given line.

Answer 19

so how do i solve for y do I have to get it to the other side

Answer 20

yeap, the slope of that lin is 3
so, notice what mathmale said
the NEGATIVE RECIPROCAL of that, is the slope of a line perpendicular to it
thus \(\bf slope=3\implies \cfrac{3}{{\color{blue}{ 1}}}\qquad negative\implies -\cfrac{3}{{\color{blue}{ 1}}}\qquad reciprocal\implies - \cfrac{{\color{blue}{ 1}}}{3}\)

Answer 21

Ok I see now... so reciprocal is just flipping it

Answer 22

pretty much, yes

Answer 23

now do I take that and plug it into the formula

Answer 24

well... into the point-slope form, yes, assuming that you have two points to work with

Answer 25

rather one point to work with, that is, an x,y pair

Answer 26

what do I do with the -1/3

Answer 27

well, you can caress it, nurture it =)
I mean.... what's the context?

if you're looking for the equation of a line that is perpendicular to 3x+12y=-18
first off, you need a x,y pair
and you can get that from that 3x=+12y=-18
pick any "x" value
get the "y:
use that x,y pair

and then plug those two in the point-slope form, along with the negative reciprocal slope
to get the equation of a line AT THAT POINT that is perpendicular to 3x+12y=-18

say... for example, you end up with x = who knows say 7, and y = 13
so then \(\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({\color{red}{ 7}}\quad ,&{\color{blue}{ 13}})\quad
% (c,d)

\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies -\cfrac{1}{3}

\\ \quad \\
% point-slope intercept
y-{\color{blue}{ 13}}={\color{green}{ -\frac{1}{3}}}(x-{\color{red}{ 7}})\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 28

3x=+12y=-18 meant 3ex+12y=-18, jus to clarify =)

Answer 29

anyhow, so, assuming you get the pair 7,13 from that
but you can simply pick any "x", get a "y", and use the slope and slap them together in the point-slope form :)

Answer 30

rats... man, trying to clarify a typo, I end up with another typo =(

3x=+12y=-18 meant 3ex+12y=-18, jus to clarify =)
I mean
3x+12y=-18 just to clarify the clarification =)

Answer 31

anyhow... need to dash :)

Answer 32

ok thanks for your time and help I got 4