1. If you use 1 in place of x, the result is still wrong, so try putting 0 in place of x.
OpenStudy (kyanthedoodle):
Oh my god. THE LEGEND IS HERE!!!
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OpenStudy (anonymous):
solve like you would solve if it was equals
just make sure if you multiply of divide by a negative number to switch the inequality
OpenStudy (anonymous):
which one would you like to do?
OpenStudy (wintersuntime):
The first one
OpenStudy (wintersuntime):
@satellite73
OpenStudy (anonymous):
\[3(6x+2)=9\\
6x+2=3\] by dividing by 3
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OpenStudy (anonymous):
subtract 2 get \[6x=1\] then divide by 6 get \[x=\frac{1}{6}\]
OpenStudy (anonymous):
replace all the \(= \) signs by \(<\) signs
OpenStudy (anonymous):
\[3(6x+2)<9\\
6x+2<3\\
6x<1\\
x<\frac{1}{6}\] like that
others are similar
OpenStudy (wintersuntime):
I need help on the second one
OpenStudy (wintersuntime):
@satellite73
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OpenStudy (fibonaccichick666):
Do everything the same as you would if it was an equals sign. The only difference is that you need to keep track of how many times you multiply/divide both sides by a negative number. If an odd number, flip your inequality. If even, keep it the same.