Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (wintersuntime):

Can someone be nice enough to help me please I'll put the link below

OpenStudy (wintersuntime):

@Tennis5518

OpenStudy (wintersuntime):

@KyanTheDoodle

OpenStudy (kyanthedoodle):

1. If you use 1 in place of x, the result is still wrong, so try putting 0 in place of x.

OpenStudy (kyanthedoodle):

Oh my god. THE LEGEND IS HERE!!!

OpenStudy (anonymous):

solve like you would solve if it was equals just make sure if you multiply of divide by a negative number to switch the inequality

OpenStudy (anonymous):

which one would you like to do?

OpenStudy (wintersuntime):

The first one

OpenStudy (wintersuntime):

@satellite73

OpenStudy (anonymous):

\[3(6x+2)=9\\ 6x+2=3\] by dividing by 3

OpenStudy (anonymous):

subtract 2 get \[6x=1\] then divide by 6 get \[x=\frac{1}{6}\]

OpenStudy (anonymous):

replace all the \(= \) signs by \(<\) signs

OpenStudy (anonymous):

\[3(6x+2)<9\\ 6x+2<3\\ 6x<1\\ x<\frac{1}{6}\] like that others are similar

OpenStudy (wintersuntime):

I need help on the second one

OpenStudy (wintersuntime):

@satellite73

OpenStudy (fibonaccichick666):

Do everything the same as you would if it was an equals sign. The only difference is that you need to keep track of how many times you multiply/divide both sides by a negative number. If an odd number, flip your inequality. If even, keep it the same.

OpenStudy (wintersuntime):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!