Question

Write (9+6i)-(1+3i) as a complex number in standard form

Answer 1

9+6i-1+3i
=9-1+6i+3i
=8+9i

Answer 2

First you need to distribute the negative sign into (1+3i)
After doing this you should get (-1-3i)
Now all that is left to do is (9+6i)+(-1-3i)
Drop the parenthesis to get 9+6i-1-3i
Combine like terms( the first pair of like terms are 9 and -1) ( the second pair of like terms are 6i and -3i) to get 8+3i