Please Help! I will give medal to anyone who helps. Im on connections and I need help with a chemistry lab i already conducted the lab but i need help with the questions.
@welder55 on which question do you need help
All of them i am really bad at chemistry
well 1-7 at the bottom the others should be filled in
ok so lets start with second
To answer this question, you need to know the molarity equation. Do you know the molarity equation?
come one
try to find in your notes
sure take your time
wait a sec
well this is what i find on internet Molarity=(mol solute)/(L solvent)
ok?
so first i would have to find the amount of moles in NaHCO3?
Now, to find the moles of NaHCO3 used, divide the molarity of the solution by the number of Liters you used for the titration. (Don't forget to convert the mL to L) .
yes @welder55
making sence?
For the second part, you need to know the equation: M1V1=M2V2
For the first part i got a crazy number and i dont think its right @MTALHAHASSAN2
@welder55 can I help you little later because I am doing a test sorry
sorry
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1.Write the balanced equation for the reaction of acetic acid ( COOH3CH ) and sodium bicarbonate ( 3NaHCO ). What type of reaction(s) took place? \[CH_{3}COOH + NaHCO_{3} \rightarrow CH_{3}COONa + H_{2}O + CO_{2} \] I guess I'd call it an acid base reaction. I'm not sure that it fits well with anything else.
2. Calculate the number of moles of NaHCO3 that were required to neutralize the COOH3CH in the vinegar. using the balanced equation we find a molar ratio of 1:1 so one mole of NaHCO3 can neutralize one mole of CH3COOH in vinegar.
3.Calculate the molarity of the vinegar sample. (Don’t forget to convert mL to L.) \[molarity=\frac{moles}{L} \] I'm not sure how much vinegar was used. the other questions kind of build on this so this is as far as I'm going
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