Question

How do I take the integral of e^x/(4-e^x)

Answer 1

Let's say (4-e^x) =t ; differentiate both sides -e^x dx =dt , substituting t and e^xdx values back into original equation -1/t dt and taking inetgral of the new equation ∫-1/tdt = -log|t|+c and substituting t value gives -log|4-e^x| +c

Hope this answers your question.