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Mathematics 11 Online
OpenStudy (anonymous):

if 171g of sucrose is added to 500ml of water, what is the molarity?

OpenStudy (anonymous):

I know that this is chem, but I still need help!! @agent0smith

OpenStudy (anonymous):

find the molar mass of sucrose first. Convert grams sucrose into moles of sucrose, and ml into liters. Divide moles by liters

OpenStudy (anonymous):

Ok.. Let me see, how do I find the molar mass again? Don't I do the atomic mass of the element time however many g/mol there are?

OpenStudy (anonymous):

So in this case since sucrose is C12-H22-O11 I'd have to do the mass of carbon (12.0107) times 12 since there are 12 g/mol, right?

OpenStudy (anonymous):

yes! and then 22(1.01) and 11(16)

OpenStudy (anonymous):

Ok, and then after that, what would I do?

OpenStudy (anonymous):

how would you convert from grams to moles?

OpenStudy (anonymous):

you have the gram amount right now

OpenStudy (anonymous):

I'm actually not too sure.. :/

OpenStudy (anonymous):

Well, there is a formula \[grams = moles/molar mass\]

OpenStudy (anonymous):

But I don't know if this is correct or not..

OpenStudy (anonymous):

okay! then you're \[grams \times \frac{ 1 mole }{ molar mass \in grams }\]

OpenStudy (anonymous):

Um.. Okay, I'm a bit confused

OpenStudy (anonymous):

its moles times molar mass to get grams

OpenStudy (anonymous):

the unit for molar mass is grams per mol

OpenStudy (anonymous):

How do I know how many moles there are though?

OpenStudy (anonymous):

you're going to solve for it since you know the molar mass (from the periodic table) and the grams (in problem)

OpenStudy (anonymous):

Ok, so the grams are 171, right?

OpenStudy (anonymous):

And then the molar mass would be the overall c12-h22-o11 thing right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok, give me a second to solve

OpenStudy (anonymous):

Ok I got 342.3484 for the molar mass, is this correct?

OpenStudy (anonymous):

And then would I divide that number by 171?

OpenStudy (anonymous):

342 is correct but you're dividing the grams by the molar mass, so (171/342)

OpenStudy (anonymous):

that gives you moles then divide by the liters

OpenStudy (anonymous):

ok so .5?

OpenStudy (anonymous):

thats .5 liters yes

OpenStudy (anonymous):

Ok, and now how do I find the molarity? I know its something like grams/liters

OpenStudy (anonymous):

But that's where I usually mess up

OpenStudy (anonymous):

yes, M = mols/ liters we know how to find molarity (171/342) and divide by the liters

OpenStudy (anonymous):

Oh really? We use the 171/342 to find the molarity? And what about the 500ml? Is that number important?

OpenStudy (anonymous):

the 171 grams/342 grams gives moles of solute, not molarity

OpenStudy (anonymous):

Oh ok.. So it would be .5/500?

OpenStudy (anonymous):

.5 liters is the volume

OpenStudy (anonymous):

Since the moles of solute is .5

OpenStudy (anonymous):

okay, but convert ml to liters

OpenStudy (anonymous):

.5/.5

OpenStudy (anonymous):

1

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

So the molarity is 1?

OpenStudy (anonymous):

correct unless ap chem is failing me

OpenStudy (anonymous):

in which case, i am sorry but im very sure 1 is correct

OpenStudy (anonymous):

Ok, so you are sure that the given 500 ml isn't important?

OpenStudy (anonymous):

it is important though, you just used it

OpenStudy (anonymous):

I did? When.. Sorry it is late and my brain is barely functioning... lol

OpenStudy (anonymous):

you used it for the denominator of mols / liters =M

OpenStudy (anonymous):

Oh right, right! So the "scientific" answer would be \[1 * 10^-3\]

OpenStudy (anonymous):

Because .5/500 is equal to that number

OpenStudy (anonymous):

no, you need to convert that 500 on the bottom to liters

OpenStudy (anonymous):

you had it right before, .5/.5 = 1

OpenStudy (anonymous):

Oh right... Omg, I'm sorry for being soo slow! So the final FINAL answer would be 1, right?

OpenStudy (anonymous):

Si!

OpenStudy (anonymous):

Oh ok! Thank you so much for your help! I might call on you tomorrow too for another problem, I need some help on!!

OpenStudy (anonymous):

I gave you a medal and a fan too!

OpenStudy (anonymous):

aw thanks! good luck with that chem my friend!

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