Question

3log2x=4

Answer 1

Can be written as:

\[\log_{10} (2x)^{3}=4\]
(Remember Logs written without a base is always in base 10.)
By the Rules of logs...
\[(2x)^{3}=10^{4}\]
\[2x=\sqrt[3]{10^{4}}\]
Therefore...
\[x=\frac{ 1 }{ 2 }(\sqrt[3]{10^{4}})\]

You should get \[x=10.77 \]