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Mathematics 6 Online
OpenStudy (russianboss1):

Help please fan and medals 3. A ball is dropped vertically from a height of 80 meters. After each bounce, the ball reaches a maximum height equal to 60 percent of maximum height of the previous bounce. Note that you are not finding a sum here, just the height of the bounces. a. Write the first three terms of the sequence. Explain how you know what they are. b. Find the height to the nearest tenth of a meter of the ball after the eighth bounce. Show and explain your work.

OpenStudy (welshfella):

first bounce will be 60% of 80 feet second bounce will be 60% of height of second bounce , and so on...

OpenStudy (russianboss1):

ok so I just keep on going to the eigth like that?

OpenStudy (welshfella):

yes first term will be 48 , second will be 48*0.60 etc

OpenStudy (welshfella):

a quick way to find the 8th bounce woud be 4* (0.6)^7

OpenStudy (russianboss1):

so the eighth bounce is 0.1119744 ?

OpenStudy (welshfella):

no try the formula

OpenStudy (welshfella):

oh sorry - thaT FORMULA IS WRONG i made a typo its 48* (0.6)^7

OpenStudy (welshfella):

you should get 1.34 m (1.3 to nearest tenth of a meter)

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