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Mathematics 14 Online
OpenStudy (priyar):

Binomial Q..

OpenStudy (priyar):

\[\left(\begin{matrix}1000 \\ 50\end{matrix}\right) +\left(\begin{matrix}999 \\ 49\end{matrix}\right)+\left(\begin{matrix}998 \\ 48\end{matrix}\right)+.......+\left(\begin{matrix}949 \\ 0\end{matrix}\right)\]=?

OpenStudy (priyar):

@ganeshie8

OpenStudy (priyar):

@ParthKohli

Parth (parthkohli):

Hockey stick, eh? :P

OpenStudy (priyar):

no.. this is what i got as the exp. while solving a problem..

OpenStudy (priyar):

and thats not the answer..

ganeshie8 (ganeshie8):

There seems to be an issue here 1000 to 949 are 52 numbers 50 to 0 are 51 numbers

Parth (parthkohli):

Oh haha, good observation.

OpenStudy (priyar):

oops! thanks! its 950

Parth (parthkohli):

Hockey Stick Identity http://www.artofproblemsolving.com/wiki/index.php/Combinatorial_identity

OpenStudy (priyar):

pls tell me how to find the sum..

ganeshie8 (ganeshie8):

The answer is then simply \(\dbinom{1001}{50}\)

OpenStudy (priyar):

but how?

ganeshie8 (ganeshie8):

First look at what the identity says we can bother about proving afterwards

ganeshie8 (ganeshie8):

you must be familiar with pascal's triangle and how it relates to the binomial coefficients, right ?

OpenStudy (priyar):

yes..

ganeshie8 (ganeshie8):

Good. Add the blue numbers, what do you get ? |dw:1456992132781:dw|

OpenStudy (priyar):

oh ok.. i am reading from the link...pls wait..

ganeshie8 (ganeshie8):

take your time

OpenStudy (priyar):

its a bit confusing.. can you write the general formula and the one for the above exp. to make things clearer..

ganeshie8 (ganeshie8):

Forget about the link. The identity is easy if you interpret it using the pascal's triangle

OpenStudy (priyar):

yes.. i understood the actual meaning of the identity...that is if we add all the no's in a diagonal in the pascal's triangle..the sum will be equal to the number directly perpendicular to it.. and this shape looks like a hockey stick. right?

OpenStudy (priyar):

But i didn't understand the mathematical formulation of it..

ganeshie8 (ganeshie8):

\[\sum\limits_{i=r}^n \dbinom{i}{i-r} = \dbinom{n+1}{n-r}\] plugin \(n=1000,~~r = 950\)

OpenStudy (priyar):

why i=r wouldn't the "i-r" term be zero always?

OpenStudy (priyar):

@ParthKohli ?

ganeshie8 (ganeshie8):

Here \(i\) is the only variable \(n\) and \(r\) are fixed

OpenStudy (priyar):

ok now i got it! thanks @ganeshie8 !

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