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OpenStudy (tylermckinney16):
questions here
OpenStudy (tylermckinney16):
@Directrix
OpenStudy (jdoe0001):
so... what did you get for the base anyway?
OpenStudy (jdoe0001):
recall \(\bf v=\cfrac{1}{3}base\cdot height\)
OpenStudy (jdoe0001):
well, to clarify that for a pyramid \(\bf v=\cfrac{1}{3}base\ area\cdot height\)
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Directrix (directrix):
V = 1/3 * B * h where B is the area of the rectangular base of the pyramid.
224 = 1/3 * 8 * 12 * h
Directrix (directrix):
What does this equal: 1/3 * 8 * 12
@TylerMckinney16
OpenStudy (tylermckinney16):
32 @Directrix
Directrix (directrix):
Therefore,
224 = 1/3 * 8 * 12 * h
224 = 32 * h
32 h = 224 ---> Solve for h @TylerMckinney16
Directrix (directrix):
h = ?
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OpenStudy (tylermckinney16):
112?
OpenStudy (tylermckinney16):
@Directrix
OpenStudy (anonymous):
help me?!
OpenStudy (anonymous):
ΔABC with vertices A(-3, 0), B(-2, 3), C(-1, 1) is rotated 180° clockwise about the origin. It is then reflected across the line y = -x. What are the coordinates of the vertices of the image?
Directrix (directrix):
>>112? No.
Get a calculator and divide 224 by 32.
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OpenStudy (anonymous):
@Directrix help?
OpenStudy (tylermckinney16):
Oh its 7?
Directrix (directrix):
Correct.
V = 1/3 * B * h where B is the area of the rectangular base of the pyramid.
224 = 1/3 * 8 * 12 * h
224 = 32 * h
32 h = 224
h = 7
OpenStudy (tylermckinney16):
Thanks @Directrix ima post another one i got three tests so ima be up late lol