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Mathematics 23 Online
OpenStudy (tylermckinney16):

help

OpenStudy (tylermckinney16):

questions here

OpenStudy (tylermckinney16):

@Directrix

OpenStudy (jdoe0001):

so... what did you get for the base anyway?

OpenStudy (jdoe0001):

recall \(\bf v=\cfrac{1}{3}base\cdot height\)

OpenStudy (jdoe0001):

well, to clarify that for a pyramid \(\bf v=\cfrac{1}{3}base\ area\cdot height\)

Directrix (directrix):

V = 1/3 * B * h where B is the area of the rectangular base of the pyramid. 224 = 1/3 * 8 * 12 * h

Directrix (directrix):

What does this equal: 1/3 * 8 * 12 @TylerMckinney16

OpenStudy (tylermckinney16):

32 @Directrix

Directrix (directrix):

Therefore, 224 = 1/3 * 8 * 12 * h 224 = 32 * h 32 h = 224 ---> Solve for h @TylerMckinney16

Directrix (directrix):

h = ?

OpenStudy (tylermckinney16):

112?

OpenStudy (tylermckinney16):

@Directrix

OpenStudy (anonymous):

help me?!

OpenStudy (anonymous):

ΔABC with vertices A(-3, 0), B(-2, 3), C(-1, 1) is rotated 180° clockwise about the origin. It is then reflected across the line y = -x. What are the coordinates of the vertices of the image?

Directrix (directrix):

>>112? No. Get a calculator and divide 224 by 32.

OpenStudy (anonymous):

@Directrix help?

OpenStudy (tylermckinney16):

Oh its 7?

Directrix (directrix):

Correct. V = 1/3 * B * h where B is the area of the rectangular base of the pyramid. 224 = 1/3 * 8 * 12 * h 224 = 32 * h 32 h = 224 h = 7

OpenStudy (tylermckinney16):

Thanks @Directrix ima post another one i got three tests so ima be up late lol

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