Question

helpp

Answer 1

@di

Answer 2

@Directrix

Answer 3

@jhonyy9

Answer 4

@jhonyy9

Answer 5

do you understand it right sure ?

Answer 6

first you need to graph a triangle

Answer 7

@Michele_Laino

Answer 8

@Directrix

Answer 9

@robtobey

Answer 10

@jhonyy9

Answer 11

@amorfide

Answer 12

As I mentioned the other night, I am not strong on Transformational Geometry.

Let's see what we can do.

Would you read the coordinates of points A, B, and C from the graph and post them here?

@freemap

Answer 13

I forgot about that,
A -4,4
B -4,8
C 4,8

Answer 14

Okay.

Kyle does this to those points: (x,y) -> ( .5x , .5y)

He takes the point:

B( -4,8) and multiplies the x value of -4 by .5 to get -2.

He multiplies the y value of B by .5 to get 4.

B(-4,8) --> B' ((-2,4)

On Kyle's triangle, we will plot point B as (-2,4)

Do you follow that @freemap ?

Answer 15

yes @Directrix

Answer 16

Okay.

Would you take point A ( -4,4) and apply Kyle's formula to the x and then to the y and post what you get to be the coordinates of A' which is the post image of the original A?

Post what you get.

Answer 17

Remember, here is what Kyle is doing to the points: (x,y) -> ( .5x , .5y)

Answer 18

I got -2 for x and 2 for y

Answer 19

@Directrix

Answer 20

Correct

A(-4,-4) --> A' (-2, 2) We will be graphing A' later.

Answer 21

okay so I just do the same thing for B and C

Answer 22

Now, do the same for the last of Kyle's points.

C (4,8) --> C' ( , )

Answer 23

I meant C
x: 2, y: 4

Answer 24

Yes, I did B earlier in the thread as an example for you.

After you get C' coordinates, we move to Jeanne's equations.

Answer 25

A(-4,-4) --> A' (-2, 2)
B(-4,8) --> B' ((-2,4)
C (4,8) --> C' ( 2 , 4 )

I think that we should plot Kyle's points on the graph before getting Jeanne's points.

Answer 26

for some reason I just couldn't draw the dots

Answer 27

I used Desmos.com to plot the points but don't know how to get the Desmos program to join the points so I drew in the graph.

Answer 28

Let's go to Jeanne's points.

Answer 29

yes that is definitely way better than mine. Thank you

Answer 30

Jeanne

(x,y) --> (.25x , .5y )

B(-4, 8) --> B" (-1, 4)

Check that and let me know if you agree.

Answer 31

yes I agree

Answer 32

Did you look at the first image with part a,b, and c because kyle is 1/2 and 1/2, and then jeanine is 1/4 and 1/2

Answer 33

@Directrix

Answer 34

Kyle and Jeanine on the same set of axes.

Jeanine is purple; Kyle is red.

Answer 35

How long is Kyle's base?

Answer 36

8 inch

Answer 37

4 for jeanine

Answer 38

4 for Kyle base

Answer 39

Kyle base is 4; Kyle height is 2

Jeanine base is 2; Jeanine height is 2.

Did you get that?

Answer 40

actually I don't get how jeanine base is 2 I counted four squares

Answer 41

If you are looking at the graph I posted, note that that you can't just count squares.

Look at the numbers on the axes.

Two square sides make 1 unit.

Bottom Line: Divide all single unit counts by 2.

I made the same mistake.

Answer 42

oh I get it

Answer 43

Each square side is 1/2 a unit.

Tricky.

Answer 44

Kyle's base of 4 is twice that of Jeanine's 2.

Kyle's height of 2 is the same as Jeanine's height of 2.

Do you agree?

I think we need to do another unit count to be sure we did not mess up.

Answer 45

Kyles' area is 1/2 * b * h = 1/2 * 4 * 2 = @freemap