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Chemistry 6 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

OpenStudy (anonymous):

@Awolflover1

OpenStudy (photon336):

\[W = p(v_{f}-v_{i})\]

OpenStudy (photon336):

Where W = work, P = pressure, Vf = final volume, Vi = initial volume

OpenStudy (photon336):

\[\frac{ W }{ p }+V_{I} = V_{f}\]

OpenStudy (anonymous):

ok, go on....

OpenStudy (photon336):

you're looking for the final volume, all you need to do is plug in the numbers into that equation and you'll get it. we know that Work is equal to the pressure times the change in volume.

OpenStudy (anonymous):

ok....

OpenStudy (photon336):

\[\frac{ 112.4~Joules }{ 1.1~atm }+0.061~L = V_{f}\]

OpenStudy (anonymous):

then convert to Ml?

OpenStudy (anonymous):

or will that give me the right answer?

OpenStudy (photon336):

you can convert to mL if you want

OpenStudy (anonymous):

does the solution come out in Liters?

OpenStudy (photon336):

it's been a while since I've done these questions

OpenStudy (photon336):

hold on

OpenStudy (anonymous):

divide you mean....

OpenStudy (photon336):

The formula is correct I need to check the units

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I have about 7 minutes btw....

OpenStudy (photon336):

First we convert joules to L~atm. then insert this into our equation that we have. \[112.4~Joules = 1.11~L~atm \] \[\frac{ 1.11L~atm }{ 1.1~atm } +0.061L = 1.07L~1070mL \] it says expansion so our final volume must be bigger than our initial volume.

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