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OpenStudy (anonymous):
OpenStudy (anonymous):
@Awolflover1
OpenStudy (photon336):
\[W = p(v_{f}-v_{i})\]
OpenStudy (photon336):
Where W = work, P = pressure, Vf = final volume, Vi = initial volume
OpenStudy (photon336):
\[\frac{ W }{ p }+V_{I} = V_{f}\]
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OpenStudy (anonymous):
ok, go on....
OpenStudy (photon336):
you're looking for the final volume, all you need to do is plug in the numbers into that equation and you'll get it.
we know that Work is equal to the pressure times the change in volume.
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OpenStudy (anonymous):
or will that give me the right answer?
OpenStudy (photon336):
you can convert to mL if you want
OpenStudy (anonymous):
does the solution come out in Liters?
OpenStudy (photon336):
it's been a while since I've done these questions
OpenStudy (photon336):
hold on
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OpenStudy (anonymous):
divide you mean....
OpenStudy (photon336):
The formula is correct I need to check the units
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
I have about 7 minutes btw....
OpenStudy (photon336):
First we convert joules to L~atm.
then insert this into our equation that we have.
\[112.4~Joules = 1.11~L~atm \]
\[\frac{ 1.11L~atm }{ 1.1~atm } +0.061L = 1.07L~1070mL \]
it says expansion so our final volume must be bigger than our initial volume.