Question

What is the direct variation equation for the above table, using t for sales tax and p for price?

t = p + 0.06
t = 0.06p
t =
t =

Answer 1

the table above? you must have posted above the screen, since it's not very noticeable

Answer 2

posted it rather... anyhow.. got table?

Answer 3

t = p + 0.06
t = 0.06p
t =
t =

Answer 4

well, lets tak a look at ... hmm say the 3rd value for example
\(\begin{array}{ccllll}
price&sales\ tax\\
(x)&(y)
\\\hline\\
1.00&0.06\\
2.00&0.12\\
3.00&0.18&\impliedby this\ one\\
4.00&0.24
\end{array}
\\ \quad \\
\begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{\color{brown}{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{\color{brown}{ n}}&\cdot&x
\\\hline\\
&& y={\color{brown}{ n }}x
\end{array}\\ \quad \\
\\ \quad \\
y = 0.18\qquad x=3.00\qquad thus\implies 0.18={\color{brown}{ n}}\cdot 3.00
\\ \quad \\
\textit{solve for }{\color{brown}{ n}}\ or\ {\color{brown}{ constant\ of\ variation}}\)

Answer 5

what would that give you for "n"?

Answer 6

i think its 0.54 if i did it the right way

Answer 7

well... how did you get 0.54 anyway?

Answer 8

0.18 x 3.00

Answer 9

hmmm to get "n", you'd want to divide both sides by 3.00

Answer 10

0.06

Answer 11

yeap \(\bf y = 0.18\qquad x=3.00\qquad thus\implies 0.18={\color{brown}{ n}}\cdot 3.00
\\ \quad \\
\cfrac{0.18}{3.00}={\color{brown}{ n}}\implies 0.06=n\qquad thus
\\ \quad \\
y={\color{brown}{ n}}x\implies y={\color{brown}{ 0.06}}x\)

Answer 12

well, in this case.. price (p) is the "x" and the tax(t) is the 'y" or dependent
so, that'll make it \(\bf t={\color{brown}{ 0.06}}p\)

Answer 13

Find the constant of variation, k, for the above table. What does this represent? how would i find this out using the same table we did? i just need steps

Answer 14

heheh
well.. read above what "n: is :)

Answer 15

\(y = 0.18\qquad x=3.00\qquad thus\implies 0.18={\color{brown}{ n}}\cdot 3.00
\\ \quad \\
\textit{solve for }{\color{brown}{ n}}\ or\ {\color{brown}{ constant\ of\ variation}}\)

Answer 16

if you want to make it a "k" then, so \(y = 0.18\qquad x=3.00\qquad thus\implies 0.18={\color{brown}{ k}}\cdot 3.00
\\ \quad \\
\textit{solve for }{\color{brown}{ k}}\ or\ {\color{brown}{ constant\ of\ variation}}\)

Answer 17

oh so theres no differences its just the variables that are

Answer 18

well, what you found,when solving for "n", was the "constant of variation", that's what "n" is, and n = 0.06 :) or k if you wish to call it that

Answer 19

oh okay thank you

Answer 20

yw