Calculus @Michele_Laino

Question

studygurl14 · Answer

attachment

studygurl14 · Answer

@satellite73

studygurl14 · Answer

@satellite73 @pooja195

anonymous · Answer

we can to this without calc

studygurl14 · Answer

Ok,how?

studygurl14 · Answer

sorry, openstudy keeps glitching

anonymous · Answer

no problem

anonymous · Answer

start at time zero (20 minutes in the past , we can adjust right?)

anonymous · Answer

it was $70$ above room temp
in 20 minutes it was $60$ above room temp
so it took 20 minutes to cool by a factor of $\frac{6}{7}$ 
you can use $$F(t)=70\times \left(\frac{6}{7}\right)^{\frac{t}{20}}$$ as your function

anonymous · Answer

now don't forget we are starting 20 minutes in the past, so 15 minutes from now is 35 minute all together

anonymous · Answer

Although I believe it wasn't included in the question, the rate of change depends on Delta T. So in time, the rate of temperature change decreases.

anonymous · Answer

$$F(t)=70\times \left(\frac{6}{7}\right)^{\frac{t}{20}}\
F(35)=70\times \left(\frac{6}{7}\right)^{\frac{35}{20}}$$

anonymous · Answer

we can do it a harder way if you like

anonymous · Answer

tbh I'm a chem e. grad. and I can't focus because I'm thinking of all the parameters etc. that isn't given. It maybe an easy one as you said, if they were meant to be omitted.