Please help! The second term of arithmetic sequence is 7. The sum of the first 4 terms of the arithmetic sequence is 12. Find the the first term a1, and tje common difference, d, of the sequence.
2nd term = a1 + d where a1 = first term and d = common difference so we can write a + d = 7
* a1 + d
do you know the formula for the sum of n terms of an arithmetic sequence?
hmm. i'm talking to myself...
an= a1 + (n -1)d
Why not let n= {1, 2, 3, 4} and write out \[a _{n}=a _{1}+(n-1)d \]
for each of those n values? This might help you find the unknowns, which are \[a _{1}~and~r\] ... where a1 is the first term and r is the common difference (not common ratio).
Note that because the second term is 7, the formula given about would come out as follows for n=2 (2nd term):\[a _{2}=a _{1}+(2-1)d\]=7
Thus, \[a _{2}=7=a _{1}+(2-1)d\]
What do i do nxt? To find the first term?
This question needs attention. Its been long time I was dealing with these things
What must you do to "solve" this problem? What are your goals? If you can answer these questions, then perhaps "what to do next?" will be clearer.
@welshfella
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