can you check me? (Alg II rational equations) I medal!
\[\frac{ 21 \pm \sqrt{-1,169} }{ 2*7 }\]
original equation:\[\frac{ 6 }{ x-1 }=\frac{ 4 }{ x-2 }+\frac{ 2 }{ x+1 }\]
Multiply both sides by x-1 \[\frac{(x-1)*6}{x-1} = \frac{(x-1)*4}{x-2} + \frac{2*(x-1)}{x+1}\]
(x-1) gets cancelled in the left side of the equation Multiply both sides by x-2 and x+1 \[6(x+2)(x+1) = \frac{4(x-1)(x-2)(x+1)}{(x-2)} + \frac{2(x-1)(x-2)(x+1)}{(x+1)}\]
Did you do the following?
yes
It looks like all the x's get cancelled
How did you get an irrational number for your x
because after you finish cancelling then you have to foil the rest of the parenthesis to get 7x^2-21x+26, and since that doesn't factor I need to use quadratic formula
\[6(x-2)(x+1) = 4(x-1)(x+1) + 2 (x-1)(x-2)\]
\[6x^2-6x+12 = 4x^2 -4 +2x^2 -6x + 4\]
Do you see what I mean
okay yes, I do
A solution doesn't exist for this problem
that makes perfect sense! thank you!
I messed up one number and then I sent myself down quadratic formula road :/
That happens! Glad you've finally understood :)
let me know if you need any help!
To be honest I hope I don't. But if I do I know who to reach :)
Goodluck!
... and I'm back @thushananth01 :/ soo how did you get 12? I got -12
Shoot! That's a -12, you are right, but that does not change the coefficient of x or x squared
so it will still cancel all?
It will cancel all the x's and x squared \[6x^2-6x-12 = 4x^2-4+2x^2-6x+4\] \[(-4x^2 - 2x^2) +6x^2- 6x -12 = 4x^2-4+2x^2-6x+4 +(-4x^2-2x^2)\]
\[-6x - 12 = -4 -6x +4\] Now 6x will get cancelled you will end up with \[-12 = 0\] which is absolutely not a solution
I don't follow... what are those parenthesis?
@thushananth01
The paranthesis shows that I am subtracting -4x^2 -2x^2 in both sides
ooh I see I thought it was multiplication
No, did you understand ?
I do now :D
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