Question

Can someone go over my work please?

Answer 1

I got \[x ^{2} \approx 10.81256\]

Answer 2

Wow! um hold on this is going to take me a while!

Answer 3

Okay, thanks!

Answer 4

hi flower girl

Answer 5

Hello! @kiity
I am getting different answers! :/ 3rd time trying! :) I got this... sorry for the wait @Kdr1308

Answer 6

I am not getting a answer.. :( I am not sure I think this is a invalid question... or incomplete input...

Answer 7

thanks for medal befor

Answer 8

Ah, okay... I wasn't quite sure if it was or not.. ugh FLVS

Answer 9

here is a medal

Answer 10

Where did you get that question Kdr?

Answer 11

Sorry It just doesn't make sense! Or doesn't even come out with a question.

Answer 12

I asked a teacher working with me in the IB program if she could give me some extra problems to work on, and she sent me to a few links with problems to work out.

Answer 13

Thanks @Flower-girl

Answer 14

You Welcome @Kdr1308 :)

Answer 15

I'll show my written work if that'll help all of you understand my answer better...

Answer 16

Letting --> \[\sqrt{\sqrt{5}+2} + \sqrt{\sqrt{5}-2} \over \sqrt{\sqrt{5}+1} \] = a

Answer 17

I'll get --->
\[x = a + \frac{ a }{ 2 } - \sqrt{(\sqrt{2}-1)^{2}} = \frac{ 3 }{ 2 }a - (\sqrt{2}-1) = \frac{ \sqrt{2} }{ 2 } + 1 \rightarrow x^2 = \frac{ 3 }{ 2 }+\sqrt{2}\]

Answer 18

Using that i got 2 possible answers of \[ x \approx 3.288246 \] or \[x^2 \approx 10.81256\]

Answer 19

I am not in this form of math yet. I am still learning, so, I wouldn't say anything, 1/4 chances of being correct. :).

Answer 20

@Jaynator495