question
suppose i did two experiments simeltaneously with some decaying radioactive material, experiment 1: I dump \(m_1 kg\) decaying material into a container and wait for a week and then dump \(m_2 kg\) into the same container and wait for another week, and I note down the total amount of material remaining at the end of two weeks. experiment 2: I dump \(m_1 kg\) decaying material into a container and wait for a week and then dump \(m_2 kg\) into a DIFFERENT container and wait for another week, and I note down the total amount of material(i.e sum of mass in both containers) remaining at the end of two weeks. will the result of both be equal?
@ganeshie8
Well! In my opinion the total product im both the cases will be identical !!!!
In*
even I feel that the two cases will be identical. (because of principle of superposition) but need confirmation :)
Okk. We can do it in this manner 1).. We have mass m1 in container and u observed it for a week then the conc• remaining at that time would be m1e^-k and if u put m2 at that time u will have its decay also occuring at the same rate that is k... So finally after two weeks u would be having this m1e^-2k + m2e^-k
And as for the secomd case we would be having furst half of the problem idenrical to the 1st ..Now you have put a mass m2 in another container there also it decays at a rate k , then we would be having at the end of two weeks Conc from first container =m1e^-2k Conc from 2nd container=m2e^-k If we add the two we will get the same resupt as that for 1st..
for the first case, you need to take into account the fact that total mass at one week is m2 + whatever is left of m1
Yes that will be taken .....sorry i didn't consider it... So the total mass would now dissociate with rate constant k
well..yea it checks out \[(m_1 e^{-k} +m_2)e^{-k}\\\]
which gives \[m_1e^{-2k}+m_2e^{-k}\]
thanks :)
U r correct!!
Nice!
Join our real-time social learning platform and learn together with your friends!