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I will give a medal, no direct answers.

Find the area of a triangle whose base is 2√3 in. and height is 3√3 in.

6√3 in.²

9 in.²

18 in.²

Question

Image below
I will give a medal, no direct answers.


Find the area of a triangle whose base is 2√3 in. and height is 3√3 in.

6√3 in.²

9 in.²

18 in.²

sagewilson · Answer

attachment

directrix · Answer

The area of a triangle is found by:

A = (1.2) * b * h

sagewilson · Answer

Okay thank you, but how would I figure out the value of 2√3 and 3√3 or would I just have to multiply them and the √3 would stay the same?

directrix · Answer

A = (1/2) * 2√3  * 3√3

directrix · Answer

A  =  (1/2) * 2  *  3  √3 * √3

What is square root of 3 times square root of 3?

sagewilson · Answer

Wait, how did you get √3 at the end of the equation?

directrix · Answer

There are two square roots of 3 in the problem.

I moved them so that they are together.

The problem is the same.

sagewilson · Answer

Okay.

sagewilson · Answer

The square root of 3 times the square root of 3 would be 2.99999997378

directrix · Answer

>> the √3 would stay the same?   No.

That is why I put them together 

So that you could multiply √3 * √3 and get √9  which is just 3

sagewilson · Answer

Oh right I did it wrong.

directrix · Answer

A = (1/2) * 2 * 3 √3 * √3

A = (1/2) * 2 * 3  * 3

A =

sagewilson · Answer

It would be 9in

directrix · Answer

9 square inches.  

Area is measured in square units.

sagewilson · Answer

Alright. Thank you for your help.

directrix · Answer

You are welcome.