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Mathematics 22 Online
OpenStudy (anonymous):

What is the equation of a horizontal line passing through the point (2, 10)? y = 12 x = –8 y = 10 x = 2

OpenStudy (anonymous):

y = 10

OpenStudy (kdr1308):

y = 10 bc it is passing through the y-axis

OpenStudy (anonymous):

Thank you!

OpenStudy (kdr1308):

Np, any more questions always feel free to ask

OpenStudy (anonymous):

Actually I have a question on rate of change it has been a subject i have always struggled with please help explain?

OpenStudy (kdr1308):

Hold on, is this FLVS? Just wondering

OpenStudy (anonymous):

? flvs?

OpenStudy (kdr1308):

Nevermind then, But do you want to know how to find the average rate of change?

OpenStudy (kdr1308):

It's pretty much the same thing as slope

OpenStudy (anonymous):

how so? It confuses me when I go through my work and see rate of change but it didnt really explain what to do --- it just showed and answer and I was like, but HOW did that happen where did you get that answer?

OpenStudy (kdr1308):

Okay let me use this as an example to show you

OpenStudy (anonymous):

okay Note book and pencil is ready to learn!

OpenStudy (kdr1308):

We know that the slope is rise over run, correct?

OpenStudy (kdr1308):

In this case it's average rate of change

OpenStudy (anonymous):

Yes ma'am rise over run and m=y-y1/x-x1

OpenStudy (kdr1308):

Great job, so when trying to find the rate of change we are going to want to find the values that they are wanting to know the distance between. This question is asking the change between 5 and 3. So your work should look something like this --> \[305-126 \over 5-3\] \[y_1 - y_2 \over x_1 - x_2\]

OpenStudy (kdr1308):

See the relationship between my work and the table?

OpenStudy (anonymous):

Yes ma'am I do -- trying to write it all down so that I do not forget --!

OpenStudy (anonymous):

oooh okay I think I understand that fairly well!

OpenStudy (anonymous):

wait, what if there is a question that gives you two x values?

OpenStudy (kdr1308):

Its asking for the average rate of change between 5 and 3

OpenStudy (anonymous):

it would be 189/2 =94.5

OpenStudy (kdr1308):

Wait.

OpenStudy (anonymous):

yes ma'am

OpenStudy (kdr1308):

Its 350 not 305. --> this is what it should look like |dw:1457496850131:dw|

OpenStudy (kdr1308):

Now it gives us two possible answers of B or C. We know it cant be c because m/s is speed not distance

OpenStudy (anonymous):

oooh okay that makes more sense hah sorry misread on my side

OpenStudy (kdr1308):

I'm not the best at explaining so hopefully this helped some

OpenStudy (anonymous):

okay that makes more sense for those kinda questions thanks! Now, there is another question that is tied onto this. actually I will try to do it before asking for more help, may I ask for help or to see if i am correct after?

OpenStudy (kdr1308):

Of course

OpenStudy (anonymous):

Find the average rate of change for the given function from x = –1 to x = 4 this was the question I am stuck on when it is giving me a graph. I got the one with the chart on my end finished thank you for that but this one I am still stuck on

OpenStudy (kdr1308):

Yeah.. I get stuck on these too. Start a new question with this problem, even now in 11th grade i have troubles with these

OpenStudy (anonymous):

??? start a new equation with the slope to substitute? \[\frac{ y1-y2 }{ -1-4 }\] ?

OpenStudy (kdr1308):

these are kinda different. This is just asking for the slope

OpenStudy (anonymous):

? oh?

OpenStudy (anonymous):

im still a little confused on how to approach this question im sorry :(

OpenStudy (kdr1308):

Its okay. Ive got to head off to school, ill help later

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