Question

There are 8 milks samples- A- 30%, B-70%,C-68%,D-59%,E-90%,F-97%,G-83%, H 37%. when two samples are mixed , how many mixtures will NEVER give youv63% milk.

Answer 1

Simply when we have either of these cases:

- Both samples are > 63%
- Both samples are < 63%

The only way to obtain 63% milk is when one exceeds that and one does not. Do you see what I mean?

Answer 2

Samples > 63%:
B, C, E, F, G

Samples < 63%:
A, D, H

So your total count is 5C2 + 3C2 = 10 + 3 = 13.

Answer 3

can you please explain with an example when can we obtain 633% of milk ?

Answer 4

63% *

Answer 5

suppose we take d and e where d is 59% and e is 90 % so If I mix these two how will I get 63 % ?

Answer 6

Sorry - I have to go in a minute but
We can get 63% milk when one of the samples >63% and the other <63% are mixed in some given ratio.

Answer 7

For example, for 90 and 59, you can actually calculate the ratio. Let's say the ratio 59%:90% is \(k:1\). Then\[63 = \frac{59k + 90}{k+1}\]

Answer 8

But obviously if you mix something like 90% and 68%, there is no way to get 63% milk. The purity will have to lie somewhere between 68% and 90%.

Answer 9

oh okay ...thank you so much for your help :)

Answer 10

No problem! =)