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Mathematics 14 Online
OpenStudy (zackattack350):

Trying to study for my test later, working on practice questions. screenshot below! please explain and work with me to solve. :)

OpenStudy (zackattack350):

OpenStudy (zackattack350):

so to find the midpoint i know i gotta use the cord sets in some way. to find the distance i tthink its the same? two different equations?

rishavraj (rishavraj):

did u find the lenght of PQ ??

rishavraj (rishavraj):

*length

OpenStudy (zackattack350):

i dont exactly know how to do that. i think its some equation where i put the points of the two lines in and then solve it? @rishavraj

OpenStudy (mathmale):

Yes. Look up "distance formula" on the 'Net. You could also use the Pythagorean Theorem: x^2 + y^2 = z^2, where |z| represents the length of the hypotenuse, which in turn is the same numerical value as the distance.

OpenStudy (mathmale):

I'd suggest you sketch a diagram.

rishavraj (rishavraj):

distance between two points say (x1, y1) and (x2, y2) is \[\sqrt{(x_1 - x_2)^2+(y_1-y_2)^2}\]

OpenStudy (zackattack350):

sqrt((-10)-(-3))^2+((10)-(13))^2 sqrt(-7)^2-3^2 sqrt 49-9 sqrt 40

OpenStudy (zackattack350):

@rishavraj do i need to simplify it anymore or is that far enough?

rishavraj (rishavraj):

\[\sqrt{49 + 9} = \sqrt{58}\]

OpenStudy (zackattack350):

oh! negative and a negative! I see that now! ok so let me see if theres a sqrt of 58!

OpenStudy (zackattack350):

not a whole number one. should i leave it as a sqrt?

OpenStudy (mathmale):

Yes, that's what the instructions say. Leave it as a radical.

OpenStudy (zackattack350):

oh! and then i have to find the midpoint. is that the midpoint formula?

OpenStudy (zackattack350):

((-10)+(-3)/2,((10)+(13))/2 -7/2,23/2 -3.5,11.5 @mathmale is that correct?

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