Trying to study for my test later, working on practice questions. screenshot below! please explain and work with me to solve. :)
so to find the midpoint i know i gotta use the cord sets in some way. to find the distance i tthink its the same? two different equations?
did u find the lenght of PQ ??
*length
i dont exactly know how to do that. i think its some equation where i put the points of the two lines in and then solve it? @rishavraj
Yes. Look up "distance formula" on the 'Net. You could also use the Pythagorean Theorem: x^2 + y^2 = z^2, where |z| represents the length of the hypotenuse, which in turn is the same numerical value as the distance.
I'd suggest you sketch a diagram.
distance between two points say (x1, y1) and (x2, y2) is \[\sqrt{(x_1 - x_2)^2+(y_1-y_2)^2}\]
sqrt((-10)-(-3))^2+((10)-(13))^2 sqrt(-7)^2-3^2 sqrt 49-9 sqrt 40
@rishavraj do i need to simplify it anymore or is that far enough?
\[\sqrt{49 + 9} = \sqrt{58}\]
oh! negative and a negative! I see that now! ok so let me see if theres a sqrt of 58!
not a whole number one. should i leave it as a sqrt?
Yes, that's what the instructions say. Leave it as a radical.
oh! and then i have to find the midpoint. is that the midpoint formula?
((-10)+(-3)/2,((10)+(13))/2 -7/2,23/2 -3.5,11.5 @mathmale is that correct?
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