A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).
Alright, first, we know that we want an equation of a line that's parallel to another. In order to be parallel, the both lines MUST have the same slope
The first step here would be to find the slope of a line going through the points (8,9) and (-12,-7). Do you know how to do that or do you need help?
Help please
The formula for slope is m=y2-y1/x2-x1. Which is the change in y over change in x. Just plug everything in, and you should get a slope of -16/-20 which can be simplified to 1/8
sorry, slope of 4/5
Since you want a parallel equation, both must have the same slope. The equation for point slope form is \[y-y _{1}=m(x-x _{1})\]
Can you continue solving or do you need help?
help please
The final equation would look like this: \[y+16=\frac{ 4 }{ 5}(x+5)\]
Sorry, typo. Instead of +16, the answer is +15
Is that it??
yes, that's the final equation. But remember that i made a typo while writing the equation, so change the 16 to a 15.
Oh okay thank you soo much
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