MEDAL AND FAN
Please check my answers and help with the problems I have.

Question

MEDAL AND FAN
Please check my answers and help with the problems I have.

anonymous · Answer

attachment

anonymous · Answer

@Preetha

anonymous · Answer

@Michele_Laino

anonymous · Answer

@rishavraj

anonymous · Answer

So I think I have 2 of them that says Please Help or ...

michele_laino · Answer

for cylinder, the requested ratio, is:
$$\huge  \frac{{rh}}{{2\left( {r + h} \right)}}$$
how your teacher has defined the best shape?

anonymous · Answer

No. I have to pick which one is the best.

anonymous · Answer

So are my other answers ok?

michele_laino · Answer

please wait, I'm checking...

anonymous · Answer

Oh ok cool. Its alright.

michele_laino · Answer

for the first one, I choose the cube, since the ratio $volume/area$ is the littlest
it is suffice to consider a cube, a sphere, and an equilateral cylinder, such that the radius of the sphere is equal to the base radius of cylinder, and both are equal to the side of the cube

anonymous · Answer

Oh ok. It makes sense.

michele_laino · Answer

namely the cube encloses the same volume, within the larger surface area

anonymous · Answer

Was that for (a.) or (b.) ?

michele_laino · Answer

I think that for $a)$ we have to choose a cube with a high volume
and for $b)$ we have to choose a cube with larger surface

michele_laino · Answer

since if we have more volume of ice, then more ice will be melted

anonymous · Answer

Got it. This is like combination of Science and Math where I fail my classes and has the lowest score on it. :(

michele_laino · Answer

for option b), please keep in mind that the melting speed of ice is proportional to the Surface of the cube

anonymous · Answer

It does not say anything about melting speed though.

michele_laino · Answer

it comes from the text of question 3b)

anonymous · Answer

Oh ok. 
How about #4? How would I do my cube?

michele_laino · Answer

I suggest this method:
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