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Mathematics 5 Online
OpenStudy (cloverracer):

algebra II question, see attachment!

OpenStudy (cloverracer):

Determine whether each function has a maximum or minimum value. Then find the value.

OpenStudy (cloverracer):

@Directrix

OpenStudy (fortytherapper):

Let's picture a parabola, which is \[x^{2}\] If it's positive, that means the parabola is opening upwards. Would the curve be a maximum or minimum? (The curve is at the bottom of the parabola) If it's negative, \[-x ^{2}\]it would be opening downwards. Would the curve be a maximum or minimum in that case? (The curve is at the top of the parabola)

Directrix (directrix):

@CloverRacer If you go over to Desmos.com, you can graph the function and see the value of the maximum. Go there and enter this equation: y = -x^2 + 4x - 4

OpenStudy (cloverracer):

okay on it.

Directrix (directrix):

Great. The graph is fairly easy to use.

OpenStudy (cloverracer):

Yeah, I regularly use that website. It's a lifesaver. I got 2 as the x-intercept and -4 as the y-intercept.

Directrix (directrix):

Let me see what I got. I'll snip and clip, and paste it here.

OpenStudy (cloverracer):

So (2,0) is the maximum point?

Directrix (directrix):

The maximum value is the y value that is the largest of all y values of the function. The maximum VALUE of y = 0. The coordinates of the the maximum POINT is (2,0).

Directrix (directrix):

@CloverRacer The maximum value of y is what?

OpenStudy (cloverracer):

Ohh okay so the answer would be a minimum value? The maximum value of y is 0

Directrix (directrix):

No. Look at the graph. >> minimum value? We are doing maximum values of y. The biggest value of y on the function on the graph. Try again.

OpenStudy (cloverracer):

i'm a little confused and don't know how to get it.

OpenStudy (cloverracer):

I know it's going to be negative because the parabola is downward.

Directrix (directrix):

It will not be negative. I think you have maximum and minimum confused. Look at the graph.

Directrix (directrix):

The largest y will ever be in its entire life in this problem is zero.

OpenStudy (cloverracer):

ohh okay i see.

OpenStudy (cloverracer):

so it's maximum; 0?

Directrix (directrix):

Maximum value is 0

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