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OpenStudy (calculusxy):

Can someone teach me some things about inverse variation?

OpenStudy (calculusxy):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

what things come to mind when you think of the word "inverse" ?

OpenStudy (calculusxy):

opposite

OpenStudy (calculusxy):

i know that direct variation can be calculated by \(y = kx\) and inverse variation can be calculated by \(yx = k\)

OpenStudy (calculusxy):

is that correct?

jimthompson5910 (jim_thompson5910):

you are correct on all 3 statements

jimthompson5910 (jim_thompson5910):

inverse variation is where as x goes up, y goes down, or vice versa. We "opposite" movements here in terms of algebra, multiplying x and y will give you a fixed number every time x*y = k and you can solve for y to get y = k/x

OpenStudy (calculusxy):

can you give me a problem with inverse variation?

jimthompson5910 (jim_thompson5910):

Let's say you had a rectangle and you knew the area was 120 the sides of the rectangle are unknown, but you know that there are 2 pieces of unknown info, the other 2 sides are equal to the first two unknowns so we have x and y unknown and this rectangle has area 120 so area = length*width 120 = x*y x*y = 120 as you can see, this fits the form x*y = k where k is the constant and k = 120 in this case

jimthompson5910 (jim_thompson5910):

one possible combo of x,y is x = 30 y = 4 x*y = 120 30*4 = 120 120 = 120 now let's say that x were to increase to 60. What happens to y? it would go down to y = 2. X goes up, y goes down

OpenStudy (calculusxy):

and asymptote can be calculated when the denominator equals to 0 right. so if the denominator was x - 2, then the asymptote would be 2.

jimthompson5910 (jim_thompson5910):

`and asymptote can be calculated when the denominator equals to 0 right. so if the denominator was x - 2, then the asymptote would be 2.` correct

OpenStudy (calculusxy):

okay thanks :)

jimthompson5910 (jim_thompson5910):

well you'd say x = 2 but you get the idea

OpenStudy (calculusxy):

anything else that i need to know?

jimthompson5910 (jim_thompson5910):

how about the horizontal asymptote?

OpenStudy (mathmale):

"and asymptote can be calculated when the denominator equals to 0 right. so if the denominator was x - 2, then the asymptote would be 2." More precisely, if the denominator of a rational expression happens to be zero at some x value or values, that tells you right then and there the equation(s) of the vertical asymptote(s).

OpenStudy (mathmale):

So: if the denom. were x-2, the vert. asy. would be x=2. Need to label that 2.

OpenStudy (calculusxy):

i don't know about the horizontal asymptote

OpenStudy (mathmale):

Well, let's try this: Supposing you have inverse variation: y=k/x. What happens to y as x continues to increase in magnitude?

OpenStudy (calculusxy):

y decreases

OpenStudy (mathmale):

Horiz. asy. have to do with the behavior of a rational function when x grows large, either in the positive or the neg direction. Yes, and decreases toward what value in particular?

OpenStudy (mathmale):

What if x=10, x=100, x=1000, etc.?

OpenStudy (calculusxy):

i don't know by what you meant when saying `decreases toward what value in particular`

OpenStudy (mathmale):

What if x=-10, x=-100, x=-1000, etc? What behavior do you see in y? Does y seem to have a limiting value?

OpenStudy (calculusxy):

when x increases, y decreases

OpenStudy (mathmale):

Actually, it was "when the function y decreases toward what value in particular?"

OpenStudy (mathmale):

Or, more generally, what happens to the value of y as x continues to increase in either the + or the - direction? This all has to do with limits. Hope I'm not getting too far ahead of where you are in y our present class.

OpenStudy (calculusxy):

we did not learn limits unfortunately

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