Question

Solve (z+ 7)2 = 3.

Answer 1

@Twaimz4life no direct answers plzz

Answer 2

@ayonnaleflore wht do u think ,,,,??

Answer 3

these are the answer choices thats why im kinda confused

Answer 4

u see expand it
(z + 7)^2 = z^2 + 49 + 14z

Answer 5

@ayonnaleflore u can proceed now??

Answer 6

ok so wouldn't you subtract 49 from both sides??

Answer 7

solve it as quadratic equation ok?
z^2 + 14z + 49 = 3
z^2 + 14z + 46 = 0
subtract 3 on both sides

Answer 8

ok
z^2+14z+46=0
im a little lost.....so i dont need to subract 46 from both sides do i ??

Answer 9

lol nah ...do u need to solve quadratic equations ??

Answer 10

ok so i dont know what to do then

Answer 11

http://tutorial.math.lamar.edu/Classes/Alg/SolveQuadraticEqnSummary.aspx

Answer 12

http://schools.aglasem.com/38975

Answer 13

ok so a=1 b=14 c=46

Answer 14

yup good work :))
see another way is to factorise it....bt wont be handy over here

Answer 15

\[x=-14\sqrt{12}/2\]

Answer 16

wht x ???

Answer 17

see D is Discriminant = b^2 - 4ac

Answer 18

@ayonnaleflore the error in ur equation is
\[z = \frac{ -14 \pm \sqrt{12} }{ 2 }\]

Answer 19

the equation I mentioned above is correct version

Answer 20

so \[z=-7 \pm \sqrt{12}\]

Answer 21

u can write
\[\sqrt{12} = 2\sqrt{3}\]

Answer 22

btw how can u write -7 without simplifying the root

Answer 23

so \[z=-7\pm \sqrt{3}\]

Answer 24

see it would be like
\[z = \frac{ -14 \pm \sqrt{12} }{ 2 }\]
\[z = \frac{ -14 \pm 2\sqrt{3} }{ 2 }\]

Answer 25

now u can take 2 common in numerator ..so it would be
\[z = \frac{ 2(-7 \pm \sqrt{3}) }{ 2 }\]

Answer 26

so my answer would be A??

Answer 27

and u can cancel 2 now....so it would be
\[ z = -7 \pm \sqrt3\]

Answer 28

@ayonnaleflore yeah :))

Answer 29

ok thank you