Find a vector that is perpendicular to the plane passing through the three given points.
@mathmale
Call your 3 given points A, B and C. Construct AB by drawing a vector from A to B. Construct AC by drawing a vector from A to C. Take the cross product of AB and AC. This will give you the direction vector of a vector perpendicular to the given plane.
OK
is this the correct answer (21,63,7)
@mathmale
I haven't actually done the problem. I need to see your work to give you meaningful feedback. AB and AC are both new vectors in the plane. show how you obtained your AB and AC, and how you found their cross product.
You wanted to know whether (21,63,7) is the correct answer. First of all, please use < and > to denote "vector." <21,63,7> Now I see that all three coordinates can be divided by 7 (a common multiple). Do this division now, please.
Unfortunately, this result does not match any of the three possible answer choices. We'll need to review your calculations.
SO IS <3,9,1> NOT THE RIGHT ANSWER?
@mathmale
It doesn't agree with any of the 3 answer choices. The more of your work you show, the better I can give you feedback on it.
I should have asked you to use the original labels for your three points. They are P(3,0,0), Q(0,2,-9) and R(-2,0,6). Find the vectors PQ and PR and then find the cross product of these two vectors. I need to see your work if you want feedback on it.
i really dont know how to solve it, can you walk me through it
@mathmale
What are the coordinates of points P and Q?
P(3,0,0), Q(0,2,-9
Good. Now please find the vector FROM P TO Q.
Also find the vector from P to R.
What is the vector from P to Q? <0-3 , 2- 0, 9 -0 > = <-3, 2, 9 > Find the vector from P to R next.
What further help need you before you could confidently proceed on your own to solve this problem?
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